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Today's Hip-Hop Math Problem

Solve:

Dark skin girls > light-skinned
Light skin girls ≤ dark-skinned

where i=disagree, homeboy

Comments

( 9 SHOTS LICKED — LICK A SHOT )
dreamweasel
Mar. 4th, 2008 02:31 pm (UTC)
some girls > others
some girls > others

some girls' mothers > other girls' mothers
tritium
Mar. 4th, 2008 04:09 pm (UTC)
Ah, so in other words, motherhood is monotonic over the total order of girls.
lucifrix
Mar. 4th, 2008 04:39 pm (UTC)
I think I love you.
lucifrix
Mar. 4th, 2008 04:40 pm (UTC)
Solution: Logic classes for whoever formulated that problem. :)
hipsterdetritus
Mar. 4th, 2008 06:30 pm (UTC)
[k]+[rs] = 1
[x] = brown-skin woman; [y] = queen; [z] = ho

If [x] = [y]; [x] ≠ [z]. ([x] + [z]) = the bo.
dreamweasel
Mar. 4th, 2008 07:13 pm (UTC)
the girl : crafty :: ice : cold
picodulce
Mar. 4th, 2008 07:20 pm (UTC)
where do you see this logic? I see it the other way in the hip hop conundrums.
ludickid
Mar. 4th, 2008 07:38 pm (UTC)
Don't blame me, blame Del.
feisty_robot
Mar. 4th, 2008 07:38 pm (UTC)
If rap was grad school, I'd be the principle investigator.
For all ladies L, we construct a set L* such that every member of this is set is also a member of the set of young people, and a member of the set of the light-skinned breed. By induction we can prove that every member of the set L* has what Big Daddy Kane needs.
( 9 SHOTS LICKED — LICK A SHOT )